How do you find the inverse of #y=log(50x)#?

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Answer 1 · 2015-12-01T16:04:07

#f^-1(x)=10^x/50#

Write as #y=log_10(50x)#.

Switch the #x# and #y# and solve for #y#.

#x=log_10(50y)#

#10^x=10^(log_10(50y))#

#10^x=50y#

#y=10^x/50#

#f^-1(x)=10^x/50#