Question

How do you find the inverse of `y = log_5x`?

Answer 1

The inverse is `y^-1=5^x`

Explanation:

It is `log_5 x=y=>x=5^y=>y^-1=5^x`

Answer 2

`x= 5^y`.

Explanation:

Raise both sides to the power of 5.
`m^(log base m` is like 'sin arc sin' operator that is the operation, in succession, with 'an operator and its inverse'.
Logarithmic function is the inverse of power function of the base. For example, `lne^n` = n.and `e^lnm`.= m.

Answer 3

The answer is `log_x5`

Explanation:

Here `y=log_5x`
`:.` inverse of y = `1/y=1/(log_5x)=(cancel(log_5x)*log_x5)/cancel(log_5x)=log_x5`

Is it correct?