How do you find the inverse of #y=log_8x#?
1 Answer
Jan 23, 2016
Explanation:
To find the inverse function the subject of the formula is
changed to x.
Using:
# log_b a = n rArr a = b^n # then
# log_8 x = y rArr x = 8^y #
# rArr f^-1(x) = 8^x #