# How do you find the inverse of y=log(x+1)?

Jun 14, 2016

#### Answer:

$y = {10}^{x} - 1$

#### Explanation:

As $y = \log \left(x + 1\right)$

$x + 1 = {10}^{y}$ and

$x = {10}^{y} - 1$

Hence inverse function of $y = \log \left(x + 1\right)$ is

$y = {10}^{x} - 1$