How do you find the inverse of #y=log(x+4)#?

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Answer 1 · 2015-11-23T02:51:34

#y=10^x-4#

Flip the #x# and #y#.

#x=log(y+4)#

We want to solve for #y#.
Remember that #log(y+4)# can also be written as #log_10(y+4)#.

#x=log_10(y+4)#

#10^x=10^(log_10(y+4))#

#10^x=y+4#

#y=10^x-4#