How do you find the inverse of #y=sinx# and is it a function?

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Mar 31, 2016

Answer:

#y=sin^-1 x#

Explanation:

From the given #y=sin x#

interchange the variables first

#x=sin y#

then solve for y in terms of x

#sin^-1 x=sin^-1(sin y)#

#sin^-1 x=y#

#y=sin^-1 x#

God bless...I hope the explanation is useful.

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Write your answer here...
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Explanation

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2
Mar 31, 2016

Answer:

Y= sinx
Y inverse = inverse of sinx
But inverse of sinx= cosecantx
Therefore 1/y=cosecantx
1=ycosecantx

Explanation:

First you are to find the inverse of both sides of the equation.
Y inverse = 1/y
Sinx inverse =1/sinx
But 1/sinx= cosecantx.
Substitute into the original equation
I/y=cosecantx
Cross multiplying
I=ycosecantx

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