How do you find the inverse of #y=sinx# and is it a function?

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Answer 1 · 2016-03-31T08:40:47

#y=sin^-1 x#

From the given #y=sin x#

interchange the variables first

#x=sin y#

then solve for y in terms of x

#sin^-1 x=sin^-1(sin y)#

#sin^-1 x=y#

#y=sin^-1 x#

God bless...I hope the explanation is useful.