# How do you find the Least common multiple of 20y, 14y^2?

Nov 30, 2016

$L C M = {2}^{2} \cdot 5 \cdot 7 \cdot {y}^{2} = 140 {y}^{2}$

#### Explanation:

Factorize the two expressions:

$20 y = {2}^{2} \cdot 5 \cdot y$
$14 {y}^{2} = 2 \cdot 7 \cdot {y}^{2}$

The LCM is the product of all factors - common or not common - taken once with the highest exponent.

$L C M = {2}^{2} \cdot 5 \cdot 7 \cdot {y}^{2} = 140 {y}^{2}$