How do you find the lengths of the three legs of the triangle if one leg of a right triangle is 3 more than twice the length of the other and the hypotenuse is 3 times the length of the short leg?
Let the smallest side of the triangle is QR, Hypotenuse is PR, PQ is the other side.
Let the length of the smallest side QR measures "a" unit.
as per the question , Hypotenuse , PR is 3.a = 3a
The side PQ has length , as per question; 2a + 3
the three sides are 3a, a and 2a + 3 respectively.