# How do you find the limit of #(-2x^2+x)/x# as x approaches 0?

##### 1 Answer

May 21, 2016

#### Answer:

1

#### Explanation:

If we substitute x = 0 into the function we obtain

#0/0#

which is indeterminate.However, factorising the numerator gives:

#(x(-2x+1))/x=(cancel(x) (-2x+1))/cancel(x)=-2x+1# now

#lim_(xto 0)(-2x+1)=0+1=1#

#rArrlim_(xto 0)(-2x^2+x)/x=1#