What is the limit of #(x^2-1)/(x-1)# as #x# approaches 1? Precalculus Graphing Rational Functions Limits - End Behavior and Asymptotes 2 Answers GiĆ³ Jul 3, 2018 Answer: I tried this: Explanation: I would try manipulating it: #lim_(x->1)(x^2-1)/(x-1)=lim_(x->1)[cancel((x-1))(x+1)]/cancel((x-1))=2# Jim G. Jul 3, 2018 Answer: #2# Explanation: #lim_(xto1)(x^2-1)/(x-1)# #=lim_(xto1)(cancel((x-1))(x+1))/cancel((x-1))=1+1=2# Related questions What is the limit of the greatest integer function? What is the limit of #f(x)=4# as #x# approaches 1? What is the limit of #f(x)=4# as #x# approaches #pi#? How do I find the limit of #(xy)/sqrt (x^2+y^2)#? What is the limit of #(2-sqrt(x))/(4-x)# as #x# approaches 4? What is the limit of #x/3# as #x# approaches 6? What is the limit of #(x^2-4)/(x-2)# as #x# approaches 2? What is the limit of #(2x-1)/(4x^2-1)# as #x# approaches #-1/2#? What is the limit of #sinx# as #x# approaches infinity? What is the limit of #(x-4)/x# as #x# approaches 4? See all questions in Limits - End Behavior and Asymptotes Impact of this question 397 views around the world You can reuse this answer Creative Commons License