# How do you find the limit of #(3x + 9)/(x^2 - 9)# as x approaches -3?

##### 2 Answers

Jul 8, 2018

#### Answer:

#### Explanation:

Given:

First factor both the numerator and denominator. Note that the denominator is the difference of squares,

Now take the limit at

Jul 8, 2018

#### Answer:

#### Explanation:

#=lim_(xto-3)(3cancel((x+3)))/(cancel((x+3))(x-3))#

#=lim_(xto-3)3/(x-3)=3/(-6)=-1/2#