Question

How do you find the Limit of `ln[(R-3)/(R-2)]` as R approaches infinity?

Answer 1

`lim_(R->oo) ln((R-3)/(R-2)) =0`

Explanation:

Dividing numerator and denominator of the rational function by `R` you have:

`lim_(R->oo) ln((R-3)/(R-2)) = lim_(R->oo) ln((1-3/R)/(1-2/R))=ln1 = 0`