How do you find the local extrema for #y=sqrtx/(x-5)#?
1 Answer
There is none.
Explanation:
First find the derivative and set the derivative equal to 0:
Using the quotient rule.
We now need to find the roots of this equation:
But there is a problem in finding the
Notice that we would have to take the square root of a negative so we do not have a value for
graph{sqrt(x)/(x-5) [-10, 10, -5, 5]}
As a result of the above and a quick look at the graph we can see that there are no turning points and as such there are no local extrema.