# How do you find the magnitude <2,-3>?

Aug 11, 2016

$| | A | | = \sqrt{13} \text{ } u n i t$

#### Explanation:

$\text{the magnitude of "A= " will be " ||A||=sqrt(x^2+y^2)," if A= < x, y>}$

$A = < 2 , - 3 >$

$x = 2 \text{ ; } y = - 3$

$| | A | | = \sqrt{{2}^{2} + {\left(- 3\right)}^{2}}$

$| | A | | = \sqrt{4 + 9}$

$| | A | | = \sqrt{13} \text{ } u n i t$