How do you find the magnitude <2,-3>? Precalculus Vectors in the Plane Vector Operations 1 Answer ali ergin Aug 11, 2016 #||A||=sqrt 13" "unit# Explanation: #"the magnitude of "A=<x,y> " will be " ||A||=sqrt(x^2+y^2)," if A= < x, y>"# #A= <2,-3># #x=2" ; "y=-3# #||A||=sqrt(2^2+(-3)^2)# #||A||=sqrt(4+9)# #||A||=sqrt 13" "unit# Answer link Related questions Question #b4ef9 What is meant by a component of a vector? How do I find the vertical component of a vector? How do i find the horizontal component of a vector? Is vector addition commutative? What happens when I multiply a vector by itself? What is the definition of vector addition? How do I do vector subtraction? What is a velocity vector? How can the law of cosines be used to find the magnitude of a resultant? See all questions in Vector Operations Impact of this question 4677 views around the world You can reuse this answer Creative Commons License