# How do you find the midpoint of (10,12) (6,9)?

The midpoint of a line segment with endpoints $\left(a , b\right)$,$\left(c , d\right)$
is $\left({x}_{M} , {y}_{M}\right) = \left(\frac{a + c}{2} , \frac{b + d}{2}\right)$
$\left({x}_{M} , {y}_{M}\right) = \left(\frac{10 + 6}{2} , \frac{12 + 9}{2}\right) = \left(8 , \frac{21}{2}\right)$