How do you find the midpoint of (10,-3), (-8,-5)?

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Answer 1 · 2018-03-10T14:21:08

#(1,-4)#

Vertically: #(y_2 - y_1)=(y - y_1)#

#y_1+y_2=2y#

#y=(y_1+y_2)/2#

Horizontally: #(x_2-x_1)=(x-x_1)#

#x_1+x_2=2x#

#x=(x_1+x_2)/2#

#:.# The coordinates of the midpoint #M(x,y)# are given by:
#(x,y) = ((x_1+x_2)/2,(y_1+y_2)/2)#

#(x,y) = ((10+(-8) )/2,((-3)+(-5))/2)#

#(x,y) = ((2)/2,(-8)/2)#

#(x,y)# = #(1#,#-4)#