How do you find the midpoint of (3,1) and (7,-5)?

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Answer 1 · 2016-03-03T12:00:06

#P_("mid") = (2,-3)#

Let the first point be#" "P_1->(x_1,y_1)->(3,1)#

Let the second point be#" "P_2->(x_2,y_2)->(7,-5)#

Let the mid point be #" "P_("mid")#

The mid point between #P_1" and "P_2# is such that its coordinates are the mid point of the #x's# and the mid point of the #y's#

#P_("mid") ->(P_2-P_1)/2->(x,y)->( (x_2-x_1)/2,(y_2-y_1)/2) #

#" "= ((7-3)/2,((-5)-1)/2)#

#P_("mid") = (2,-3)#