# How do you find the midpoint of ( -3, 2 ) and ( 9, 8 )?

Jul 12, 2017

$\left(2 , 5\right)$

#### Explanation:

The midpoint of

$\left({x}_{1} , {y}_{1}\right) \text{ "&" " (x_2,y_2)" is given by } M \left(\frac{{x}_{1} + {x}_{2}}{2} , \frac{{y}_{1} + {y}_{2}}{2}\right)$

i.e. the average of the co-ordinates

so

$\left(- 3 , 2\right) \text{ "&" " (9,8)" } \implies M \left(\frac{- 3 + 9}{2} , \frac{2 + 8}{2}\right)$

#giving

$M \left(\frac{6}{3} , \frac{10}{2}\right) = M \left(2 , 5\right)$