How do you find the midpoint of ( -3, 2 ) and ( 9, 8 )?

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Answer 1 · 2017-07-12T07:42:02

#(2,5)#

The midpoint of

#(x_1,y_1) " "&" " (x_2,y_2)" is given by "M((x_1+x_2)/2,(y_1+y_2)/2)#

i.e. the average of the co-ordinates

so

#(-3,2) " "&" " (9,8)" "=>M((-3+9)/2,(2+8)/2)#

#giving

#M(6/3,10/2)=M(2,5)#