How do you find the midpoint of (5,-2), (3,-6)?

3 Answers
Apr 23, 2017

See the entire solution process below:

Explanation:

The formula to find the mid-point of a line segment give the two end points is:

#M = ((color(red)(x_1) + color(blue)(x_2))/2 , (color(red)(y_1) + color(blue)(y_2))/2)#

Where #M# is the midpoint and the given points are:

#(color(red)((x_1, y_1)))# and #(color(blue)((x_2, y_2)))#

Substituting the values from the points in the problem gives:

#M = ((color(red)(5) + color(blue)(3))/2 , (color(red)(-2) + color(blue)(-6))/2)#

#M = (8/2 , -8/2)#

#M = (4, -4)#

Apr 23, 2017

#(4,2)#

Explanation:

The midpoint of a segment with endpoints:

#A = (x_1, y_1) and B = (x_2, y_2)# has coordinates :

#[(x_1 + x_2) /2 , (y_1 + y_2)/2]#

So in this case the midpoint is:

#[(5+3)/2,(-2-(-6))/2]# => simplify:

#[8/2,(-2+6)/2]#

#(4,2)#

Apr 23, 2017

The midpoint of (5 , -2), (3 , -6) is (4 , -4)

Explanation:

The midpoint formula is #((x_1+x_2)/2 , (y_1+y_2)/2)#

For your points

#x_1# = 5 because your first point on "x" is 5 from (5,-2)

#x_2# = 3 because your second point on "x" is 3 from (3,-6)

#y_1# = -2 because your first point on "y" is -2 from (5,-2)

#y_2# = -6 because your second point on "y" is -6 from (3,-6)

From here all you need to do is substitute values.

#(((5)+(3))/2 , ((-2)+(-6))/2)#

#((5+3)/2 , (-2-6)/2)#

#((8)/2 , (-8)/2)# [Simplify your fractions by dividing]

(4 , -4)

To get a better understanding of this formula, remember that any number divided by 2 is the middle of that number. So what we are doing here is adding our points together and then dividing them by 2.
Here's a simple example:

What is the midpoint between (20 , 0) and (10 , 0)?

All I have to do is 20 + 10 = 30

and then divide by 2

#30 -: 2 = 15#

(15 , 0)

I know this is the right answer because I can add and subtract the same number from my midpoint to return to my two original points. In this case that number is 5.

15 + 5 = 20

15 - 5 = 10