# How do you find the midpoint of A(7,-2) and M(10,10)?

Midpoint is at $\left(\frac{17}{2} , 4\right)$

#### Explanation:

Solution:

$x = \frac{{x}_{a} + {x}_{m}}{2} = \frac{7 + 10}{2} = \frac{17}{2}$
$y = \frac{{y}_{a} + {y}_{m}}{2} = \frac{- 2 + 10}{2} = \frac{8}{2} = 4$

Midpoint is at $\left(\frac{17}{2} , 4\right)$

God bless....I hope the explanation is useful.