# How do you find the midpoint of S(4,-1) and T(6,0)?

Jul 14, 2016

By midpoint formula,
Midpoint of ST = $\left(5 , - 0.5\right)$

#### Explanation:

S = (4,-1) where 4 = ${x}_{\text{1}}$ and -1 = ${y}_{\text{1'}}$
T = (6,0) where 6 = ${x}_{\text{2}}$ and 0 = ${y}_{\text{2}}$

Midpoint Formula => $\left(\frac{{x}_{\text{1" + x_"2")/2 , (y_"1" + y_"2}}}{2}\right)$

Substituting the values of ${x}_{\text{1",y_"1'",x_"2",y_"2}}$ in the formula gives

$\left(\frac{4 + 6}{2} , \frac{- 1 + 0}{2}\right)$

$\left(5 , - 0.5\right)$

Jul 14, 2016

Mid point "M" is at $\left(5 , - \frac{1}{2}\right)$

#### Explanation:

Mid point "M" is at$\left(\frac{{x}_{1} + {x}_{2}}{2} , \frac{{y}_{1} + {y}_{2}}{2}\right) = \left(\frac{4 + 6}{2} , \frac{- 1 + 0}{2}\right) \mathmr{and} \left(5 , - \frac{1}{2}\right)$[Ans]