How do you find the missing term in the geometric sequence #9/4, 3/4, 1/4, 1/12, __#?

1 Answer
Dec 18, 2016

Answer:

Missing term is #1/36#

Explanation:

In the given geometric sequence #{9/4,3/4,1/4,1/12,-}#, let us first the common ratio #r#, which is the ratio between a term and its preceding term.

Note that it means that succeeding term is peceding term multiplied by common ratio.

#r=(1/12)/(1/4)=(1/4)/(3/4)=(3/4)/(9/4)# or

#r=1/12xx4/1=1/4xx4/3=3/4xx4/9=1/3#

Hence, the last missing term is #1/12xx1/3=1/36#