# How do you find the number of complex, real and rational roots of 3x^2+11x-10=0?

Nov 21, 2016

The two roots are real, but not rational given by x=$\frac{- 11 \pm \sqrt{241}}{6}$. No complex roots.

#### Explanation:

This is a quadratic expression. Quadratic formula can be used to find the roots

x=(-11+- sqrt (11^2 -4(3)(-10))) /(2(3)

= $\frac{- 11 \pm \sqrt{241}}{6}$

as can be seen now, both the roots are real, they are not rational. There are no complex roots.