How do you find the number of complex, real and rational roots of #3x^2+11x-10=0#?

1 Answer
bp
Nov 21, 2016

The two roots are real, but not rational given by x=#(-11 +- sqrt 241)/6#. No complex roots.

Explanation:

This is a quadratic expression. Quadratic formula can be used to find the roots

x=#(-11+- sqrt (11^2 -4(3)(-10))) /(2(3)#

= #(-11 +- sqrt 241)/6#

as can be seen now, both the roots are real, they are not rational. There are no complex roots.

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