How do you find the oxidation number of #N# in #NO# (nitrogen oxide)?

1 Answer
Jun 27, 2016

Answer:

#N# in #NO# has a formal oxidation number of #+II#

Explanation:

Since oxygen is slightly more electronegative than nitrogen, oxygen formally gets the electrons, to give #N^(2+)# and #O^(2-)#.

#NO# necessarily is a free radical (why necessarily?), and the single electron is placed on the nitrogen.