How do you find the partial derivative of #f(x,y) = xe^y + ye^x#?

1 Answer
May 13, 2015

First, you must bear in mind the rules for deriving #e#: the derived form of #e^f(x)# is #f(x)e^f(x)#.

The partial derivative for #x# is:

#e^y# + #y.e^x.1#

(note that the number 1 here refers to deriving the #x# in the second element of the function - no need to put that in your answer, it's jut to clear things out)

The partial derivative for #y# is:

#x.e^y.1# + #e^x#

Same logic here :)