Question

How do you find the partial derivative of `f(x,y) = xe^y + ye^x`?

Answer 1

First, you must bear in mind the rules for deriving `e`: the derived form of `e^f(x)` is `f(x)e^f(x)`.

The partial derivative for `x` is:

`e^y` + `y.e^x.1`

(note that the number 1 here refers to deriving the `x` in the second element of the function - no need to put that in your answer, it's jut to clear things out)

The partial derivative for `y` is:

`x.e^y.1` + `e^x`

Same logic here :)