How do you find the perimeter of a triangle given (2, 2), (-2, 2), and (-2, -3)?

1 Answer
Apr 21, 2018

Answer:

Perimeter is #15.4#

Explanation:

To find perimeter, we should find sum of all the three sides of the triangle formed by #A(2,2)#, #B(-2,2)# and #C(-2,-3)#

Before we do that observe that between #A# and #B#, ordinate is same and hence line joining them is parallel to #x#-axis. Further as difference between abscissa is #4#, length of #AB# is #4#.

Also observe that between #B# and #C#, abscissa is same and hence line joining them is parallel to #y#-axis. Further as difference between ordinate is #5#, length of #BC# is #5#.

As #AB# is parallel to #x#-axis and #BC# is parallel to #y#-axis, #DeltaABC# is right angled triangle and hence from Pythagoras theorem, hypotenuse #AC=sqrt(4^2+5^2)=sqrt(16+25)=sqrt41=6.403~=6.4#

and perimeter is #4+5+6.4=15.4#

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