How do you find the point (x,y) on the unit circle that corresponds to the real number $t = \frac{π}{4}$ $t=pi/4$ ?

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How do you find the point (x,y) on the unit circle that corresponds to the real number $t = \frac{π}{4}$ $t=pi/4$ ?

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Answer 1 · 2018-06-17T14:48:51

$(x, y) = (\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2})$ $color(blue)((x,y) = (sqrt2/2, sqrt2/2)$ or $(\frac{1}{\sqrt{2}}, \frac{1}{\sqrt{2}})$ $color(blue)((1/sqrt2, 1/sqrt2)$

Explanation:

http://![https://www.google.com/imgres?imgurl=http://d2r5da613aq50s.cloudfront.net/wp-content/uploads/323183.image0.jpg&imgrefurl=http://www.dummies.com/education/math/calculus/pre-calculus-unit-circle/&h=483&w=535&tbnid=MxZcZ_m0KSW-4M&tbnh=213&tbnw=236&vet=1&docid=D9LL7Xjsxq97fM]( useruploads.socratic.org )

$t = \frac{π}{4}$ $t = pi/4$

From the above diagram,

$(x, y) = (\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2})$ $color(blue)((x,y) = (sqrt2/2, sqrt2/2)$ or $(\frac{1}{\sqrt{2}}, \frac{1}{\sqrt{2}})$ $color(blue)((1/sqrt2, 1/sqrt2)$

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How do you find the point (x,y) on the unit circle that corresponds to the real number $t = \frac{π}{4}$ $t=pi/4$ ?

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How do you find the point (x,y) on the unit circle that corresponds to the real number $t = \frac{π}{4}$ $t=pi/4$ ?