How do you find the points of discontinuity of #y = (x + 4) /(x^2 - 6x + 8)#?

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Answer 1 · 2015-06-04T17:57:31

Factorise the denominator so that y= #(x+4)/((x-4)(x-2)#. The points of dicontinuity are at x=2 and x= 4