Question

How do you find the points of intersection of `r=theta/2, r=2`?

Answer 1

`(r, \theta)\equiv(2, 4)`

Explanation:

Equating given functions, `r=\theta/2` & `r=2`, we get

`\theta/2=2`

`\theta=4`

hence the point of intersection is

`(r, \theta)\equiv(2, 4)`