How do you find the polar coordinate of (-1,1)?

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How do you find the polar coordinate of (-1,1)?

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Answer 1 · 2016-03-24T10:36:42

Polar coordinates are $(\sqrt{2}, \frac{3 π}{4})$ $(sqrt2,(3pi)/4)$

Explanation:

Polar coordinates $(r, θ)$ $(r,theta)$ of rectangular coordinates $(x, y)$ $(x,y)$ are given by $r = \sqrt{x^{2} + y^{2}}$ $r=sqrt(x^2+y^2)$ and $θ = {tan}^{- 1} (\frac{y}{x})$ $theta=tan^(-1)(y/x)$ .

Hence polar coordinates of $(- 1, 1)$ $(-1,1)$ are

$(\sqrt{{(- 1)}^{2} + 1^{2}}, {tan}^{- 1} (\frac{- 1}{1}))$ $(sqrt((-1)^2+1^2),tan^(-1)((-1)/1))$ or

$(\sqrt{(1 + 1)}, {tan}^{- 1} (- 1))$ $(sqrt((1+1)),tan^(-1)(-1))$ or

$(\sqrt{2}, \frac{3 π}{4})$ $(sqrt2,(3pi)/4)$

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How do you find the polar coordinate of (-1,1)?

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