How do you find the polar coordinate of $(3, -2)$ ?

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Answer 1 · 2016-03-25T09:48:18

Polar coordinates are $(3.606,-33.69^o)$

If rectangular coordinates are given by $(x,y)$ , polar coordinates are $(r,theta)$ where

$r=sqrt(x^2+y^2)$ and $theta=tan^(-1)(y/x)$

Hence polar coordinates of $(3,-2)$ are given by

$r=sqrt(3^2+(-2)^2)=sqrt(9+4)=3.606$

and $theta=tan^(-1)(-2/3)=-33.69^o$

Hence polar coordinates are $(3.606,-33.69^o)$

How do you find the polar coordinate of (3, -2)(3, -2)?