Question

How do you find the polar coordinates of the rectangular point (-4,-4)?

Answer 1

The point #(-4,-4) is in Quadrant III

Explanation:

`r=sqrt(x^2+y^2)=sqrt((-4)^2+(-4)^2)=4sqrt2`

Now, the reference angle in Quadrant III is ...

reference angle `=tan^1(4/4)=45^0`

`theta=180^o + 45^o=225^o`

polar coordinate `(r,theta)=(4sqrt2, 225^o)=(3sqrt2,(5pi)/4)`

hope that helped