# How do you find the probability of getting a sum of 5 on the first toss of two number cubes and?

$\frac{4}{36} = \frac{1}{9}$

#### Explanation:

I'm going to assume we're using fair standard cube dice.

There are 2 dice, each with numbers 1-6. So there are 36 different possible combinations.

So how can we get a sum of 5? We can get it with:

1,4
2,3
3,2
4,1

with the first number being the first die and the second the second.

There are 4 ways to get a 5.

The probability, therefore, is:

$\frac{4}{36} = \frac{1}{9}$