# How do you find the product 14t^3u(2t^2u^2-10tu^4+2)?

Apr 9, 2017

$= 28 {t}^{5} {u}^{3} - 140 {t}^{4} {u}^{5} + 28 {t}^{3} u$
$14 {t}^{3} u \left(2 {t}^{2} {u}^{2} - 10 t {u}^{4} + 2\right)$
$= 28 {t}^{5} {u}^{3} - 140 {t}^{4} {u}^{5} + 28 {t}^{3} u$