# How do you find the product 6g^2(3g^3+4g^2+10g-1)?

$18 {g}^{5} + 24 {g}^{4} + 60 {g}^{3} - 6 {g}^{2}$
$6 {g}^{2} \left(3 {g}^{3} + 4 {g}^{2} + 10 g - 1\right)$
$18 {g}^{5} + 24 {g}^{4} + 60 {g}^{3} - 6 {g}^{2}$