How do you find the product $-9g(-2g+g^2)+3(g^2+4)$ ?

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Answer 1 · 2017-07-09T12:51:53

See a solution process below:

First, expand the terms in parenthesis by multiplying each term within the parenthesis by the term outside the parenthesis:

$color(red)(-9g)(-2g + g^2) + color(blue)(3)(g^2 + 4) =>$

$(color(red)(-9g) xx -2g) + (color(red)(-9g) xx -g^2) + (color(blue)(3) xx g^2) + (color(blue)(3) xx 4) =>$

$18g^2+ (-9g^3) + 3g^2 + 12 =>$

$18g^2 - 9g^3 + 3g^2 + 12$

Next, group like terms:

$-9g^3 + 18g^2 + 3g^2 + 12$

Now, combine like terms:

$-9g^3 + (18 + 3)g^2 + 12$

$-9g^3 + 21g^2 + 12$

How do you find the product -9g(-2g+g^2)+3(g^2+4)-9g(-2g+g^2)+3(g^2+4)?