How do you find the product of #(10n^2)/4*2/n#?

2 Answers
Dec 22, 2016

Answer:

#5n#

Explanation:

#(10n^2)/4xx2/n=(20n^2)/(4n)=(cancel((4n))5n)/cancel(4n)=5n#

Dec 22, 2016

Answer:

#5n#

Explanation:

There are 2 approaches here. We could #color(blue)"simplify"# the fractions and then multiply what remains or we can multiply the fractions and then #color(blue)"simplify"#

#color(red)"Simplify and multiply"#

To simplify we #color(blue)"cancel"# common factors between the numerators/denominators.
Here we can cancel 10 and 4 by 2 or 4 and 2 by 2. #n^2# and n have a common factor of n.

#rArr(cancel(10)^5 xxnxxcancel(n)^1)/cancel(4)^2xx2/cancel(n)^1#

#=(5nxx2)/2=(5nxxcancel(2)^1)/cancel(2)^1=5n#

#color(red)"multiply and simplify"#

#(10n^2)/4xx2/n=(10n^2xx2)/(4n)=(20n^2)/(4n)#

now simplify by cancelling.

#=(cancel(20)^5xxnxxcancel(n)^1)/(cancel(4)^1cancel(n)^1)=5n#