How do you find the product of (10n^2)/4*2/n?

2 Answers
Dec 22, 2016

5n

Explanation:

(10n^2)/4xx2/n=(20n^2)/(4n)=(cancel((4n))5n)/cancel(4n)=5n

Dec 22, 2016

5n

Explanation:

There are 2 approaches here. We could color(blue)"simplify" the fractions and then multiply what remains or we can multiply the fractions and then color(blue)"simplify"

color(red)"Simplify and multiply"

To simplify we color(blue)"cancel" common factors between the numerators/denominators.
Here we can cancel 10 and 4 by 2 or 4 and 2 by 2. n^2 and n have a common factor of n.

rArr(cancel(10)^5 xxnxxcancel(n)^1)/cancel(4)^2xx2/cancel(n)^1

=(5nxx2)/2=(5nxxcancel(2)^1)/cancel(2)^1=5n

color(red)"multiply and simplify"

(10n^2)/4xx2/n=(10n^2xx2)/(4n)=(20n^2)/(4n)

now simplify by cancelling.

=(cancel(20)^5xxnxxcancel(n)^1)/(cancel(4)^1cancel(n)^1)=5n