How do you find the product of #(3x^3)/(8x)*16/x#?

2 Answers
Jul 24, 2017

Answer:

You will need to multiply the numbers top X top, and bottom X bottom and add the exponents in the same way. After that you will need to simplify by dividing and exponent subtraction if necessary.

Explanation:

We have: #(3x^3)/(8x)*16/x#

#(3x^3)/(8x)*16/x = (48x^3)/(8x^2)to# by multiplying #3x^3*16=48x^3# and adding exponents to get the denominator: #8x*x=8x^2#

#(48x^3)/(8x^2)=(cancel(48x^3)6x)/cancel(8x^2)=6xto# by dividing #48/8# and subtracting exponents to reduce the fraction: #x^3/x^2 = x#

Then: #(3x^3)/(8x)*16/x=6x#

Jul 24, 2017

Answer:

#6x#

Explanation:

#(3x^3)/(8x) xx16/x#

If you cancel factors in the numerator and denominator first, it makes the numbers smaller.

Cancel the numbers and simplify the variables in the denominators by adding the indices:

#(3x^3)/(cancel8x) xxcancel16^2/x = (6x^3)/(x^2)#

To divide with indices, subtract them:

#(6x^3)/(x^2) = 6x#