How do you find the product of (3x^3)/(8x)*16/x?

2 Answers
Jul 24, 2017

You will need to multiply the numbers top X top, and bottom X bottom and add the exponents in the same way. After that you will need to simplify by dividing and exponent subtraction if necessary.

Explanation:

We have: (3x^3)/(8x)*16/x

(3x^3)/(8x)*16/x = (48x^3)/(8x^2)to by multiplying 3x^3*16=48x^3 and adding exponents to get the denominator: 8x*x=8x^2

(48x^3)/(8x^2)=(cancel(48x^3)6x)/cancel(8x^2)=6xto by dividing 48/8 and subtracting exponents to reduce the fraction: x^3/x^2 = x

Then: (3x^3)/(8x)*16/x=6x

Jul 24, 2017

6x

Explanation:

(3x^3)/(8x) xx16/x

If you cancel factors in the numerator and denominator first, it makes the numbers smaller.

Cancel the numbers and simplify the variables in the denominators by adding the indices:

(3x^3)/(cancel8x) xxcancel16^2/x = (6x^3)/(x^2)

To divide with indices, subtract them:

(6x^3)/(x^2) = 6x