How do you find the product of ${(4 tan (y) + 4 cot (y))}^{2}$ $(4tan(y)+4cot(y))^2$ ?

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Answer 1 · 2018-06-25T13:34:28

$16 ({tan}^{2} (y) + {cot}^{2} (y) + 2)$ $16(tan^2(y)+cot^2(y)+2)$

We are using that

${(a + b)}^{2} = a^{2} + 2 a b + b^{2}$ $(a+b)^2=a^2+2ab+b^2$
and
$tan (x) \cdot cot (x) = 1$ $tan(x)*cot(x)=1$
so we get

$16 {(tan (y) + cot (y))}^{2} =$ $16(tan(y)+cot(y))^2=$
$16 ({tan}^{2} (y) + {cot}^{2} (y) + 2)$ $16(tan^2(y)+cot^2(y)+2)$

How do you find the product of (4tan(y)+4cot(y))2(4tan(y)+4cot(y))^2?