How do you find the product of #-h(6h-1)#? Algebra Polynomials and Factoring Multiplication of Monomials by Polynomials 1 Answer smendyka Dec 28, 2016 #-6h^2 + h# Explanation: You multiply each term within the parenthesis #(color(blue)(6h - 1))# by the term outside the parenthesis (#color(red)(-h)#) making sure to manage the signs of the terms correctly. #color(red)(-h)(color(blue)(6h - 1)) -> (color(red)(-h) * color(blue)(6h)) + (color(red)(-h) * color(blue)(-1)) -> -6h^2 + h# Answer link Related questions What is Multiplication of Monomials by Polynomials? How do you multiply monomials by polynomials? How do you multiply monomials by monomials? How do you multiply #(3xy^5)(-6x^4y^2)#? How do you multiply and simplify #6ab(-10a^2 b^3+c^5)#? How do you simplify #-3a^2b(9a^2-4b^2)#? How do you multiply #y(xy^4)#? How do you multiply #(2x-1)(x^3-2x^2+3x-4)#? How do you multiply #(5n^2)(2n^5 - 2n^3 3n^7)#? How do you simplify #2t^2+(3+5)(4t)#? See all questions in Multiplication of Monomials by Polynomials Impact of this question 1664 views around the world You can reuse this answer Creative Commons License