How do you find the product of (n^2+n-2)/(n+2)*(4n)/(n-1)? Algebra Rational Equations and Functions Multiplication of Rational Expressions 1 Answer Shwetank Mauria Mar 31, 2017 (n^2+n-2)/(n+2)*(4n)/(n-1)=4n Explanation: (n^2+n-2)/(n+2)*(4n)/(n-1) =(n^2+2n-n-2)/(n+2)*(4n)/(n-1) =(n(n+2)-1(n+2))/(n+2)*(4n)/(n-1) =((n-1)(n+2))/(n+2)*(4n)/((n-1)) =(cancel((n-1))cancel((n+2)))/cancel((n+2))*(4n)/(cancel((n-1))) =4n Answer link Related questions What is Multiplication of Rational Expressions? How do you multiplying rational expressions? Is multiplication of rational expressions commutative? How do you multiply \frac{12x^2-x-6}{x^2-1} \cdot \frac{x^2+7x+6}{4x^2-27x+18}? How do you multiply and simplify to the lowest terms \frac{x^3}{2y^3} \cdot \frac{2y^2}{x}? How do you multiply \frac{5x^2+16x+3}{36x^2-25} \cdot (6x^2+5x)? How do you multiply and simplify the expression 2xy \cdot \frac{2y^2}{x^3}? How do you multiply (a^2-a-12)/(a^2-5a+4)*(a^2+2a-3)/(a^2+a-6)? How do you multiply (4(x+2))/(5x)*(6x^2)/(2x)? How do you multiply (30a^2)/(18b)*(6b)/(5a)? See all questions in Multiplication of Rational Expressions Impact of this question 1697 views around the world You can reuse this answer Creative Commons License