# How do you find the quotient (10a^3-20a^2+5a)div5a?

Jul 29, 2017

$2 {a}^{2} - 4 a + 1$

#### Explanation:

$\text{divide each term on the numerator by } 5 a$

$\Rightarrow \frac{10 {a}^{3}}{5 a} - \frac{20 {a}^{2}}{5 a} + \frac{5 a}{5 a}$

$= 2 {a}^{\left(3 - 1\right)} - 4 {a}^{\left(2 - 1\right)} + 1$

$= 2 {a}^{2} - 4 a + 1 \leftarrow \textcolor{red}{\text{ quotient}}$