How do you find the quotient #-16/0#?

1 Answer
May 16, 2018

There is no solution

Explanation:

When you write #a/b# you are looking for a third number #c# such that #c·b=a#. Is the case #12/3=4# because #4·3=12#

#-16/0# there is no number #c# such that #c·0=-16# because #0# multiplied by whichever number is allways 0

Other approach is thinking in numbers getting smaller in denominator, imagine #4/0.0000000000001# the result is bigger and bigger. but it is resolved using a process called "pass to limit" This is the reason because other responses say #oo#. But the truth is NO SOLUTION