# How do you find the quotient (6x^2+10x)div2x?

Feb 25, 2017

See the entire solution process below:

#### Explanation:

First, rewrite this expression as:

$\frac{6 {x}^{2} + 10 x}{2 x}$

Next, factor $\textcolor{red}{2 x}$ from the term in the numerator:

$\frac{\left(\textcolor{red}{2 x} \times 3 x\right) + \left(\textcolor{red}{2 x} \times 5\right)}{2 x}$

$\frac{\textcolor{red}{2 x} \left(3 x + 5\right)}{2 x}$

Then, cancel the common terms in the numerator and denominator:

$\frac{\cancel{\textcolor{red}{2 x}} \left(3 x + 5\right)}{\textcolor{red}{\cancel{\textcolor{b l a c k}{2 x}}}}$

$3 x + 5$, when $2 x \ne 0$ or $x \ne 0$