Question

How do you find the quotient of `(14y^5+21y^4-6y^3-9y^2+32y+48)div(2y+3)` using long division?

Answer 1

Quotient is `7y^4-3y+2+16`

Explanation:

`14y^5+21y^4-6y^3-9y^2+32y+48`

=`7y^4*(2y+3)-3y+2*(2y+3)+16*(2y+3)`

=`(2y+3)*(7y^4-3y+2+16)`

Hence quotient is `7y^4-3y+2+16` and remainder is `0`.