How do you find the quotient of #(3a)/(a^2+2a+1)div(a-1)/(a+1)#?

2 Answers
Aug 7, 2018

Answer:

#(3a)/((a+1)(a-1))#

Explanation:

#"factor the denominator of the fraction on the left"#

#"Change division to multiplication and turn the fraction"#
#"on the right upside down. Perform any cancelling"#

#=(3a)/((a+1)cancel((a+1)))xxcancel((a+1))/(a-1)#

#=(3a)/((a+1)(a-1))=(3a)/(a^2-1)#

Aug 7, 2018

Answer:

#(3a)/(a^2-1)#

Explanation:

#(3a)/(a^2+2a+1)/((a-1)/(a+1))#

=#(3a)/(a^2+2a+1)*(a+1)/(a-1)#

=#(3a)/(a+1)^2*(a+1)/(a-1)#

=#(3a)/((a+1)*(a-1))#

=#(3a)/(a^2-1)#