How do you find the quotient of (4t^2-1)div(2t+1)?

Nov 7, 2016

$2 t - 1$

Explanation:

$\left(4 {t}^{2} - 1\right) \div \left(2 t + 1\right) \implies$

$\frac{4 {t}^{2} - 1}{2 t + 1} \implies$

$\frac{\left(2 t + 1\right) \left(2 t - 1\right)}{2 t + 1} \implies$

$\frac{2 t + 1}{2 t + 1} \left(2 t - 1\right) \implies$

$1 \cdot \left(2 t - 1\right) \implies$

$2 t - 1$