# How do you find the quotient of (6b-12)/(b+5)div(12b+18)?

Mar 24, 2017

$= \frac{b - 2}{\left(b + 5\right) \left(2 b + 3\right)}$

#### Explanation:

$\frac{6 b - 12}{b + 5} \div i \mathrm{de} \left(12 b + 18\right)$

$\frac{\left(6 b - 12\right)}{\left(b + 5\right)} \cdot \frac{1}{\left(12 b + 18\right)}$

Factor the terms completely:
$= \frac{\textcolor{red}{\left(6\right)} \left(b - 2\right)}{\left(b + 5\right)} \cdot \frac{1}{\textcolor{red}{\left(6\right)} \left(2 b + 3\right)}$

$= \frac{b - 2}{\left(b + 5\right) \left(2 b + 3\right)}$