How do you find the quotient of #(6n^2-12n+3)div3n#?
1 Answer
Jun 4, 2018
Explanation:
#"divide each term on the numerator by "3n#
#=(6n^2)/(3n)-((12n)/(3n))+3/(3n)#
#=cancel(6)^2/cancel(3)^1n^((2-1))-cancel(12n)^4/(cancel(3n)^1)+cancel(3)/(cancel(3) n)#
#=2n-4+1/n#
