# How do you find the quotient of (6n^2-12n+3)div3n?

Jun 4, 2018

$2 n - 4 + \frac{1}{n}$

#### Explanation:

$\text{divide each term on the numerator by } 3 n$

$= \frac{6 {n}^{2}}{3 n} - \left(\frac{12 n}{3 n}\right) + \frac{3}{3 n}$

$= {\cancel{6}}^{2} / {\cancel{3}}^{1} {n}^{\left(2 - 1\right)} - {\cancel{12 n}}^{4} / \left({\cancel{3 n}}^{1}\right) + \frac{\cancel{3}}{\cancel{3} n}$

$= 2 n - 4 + \frac{1}{n}$