# How do you find the quotient of (8a^2+20a)div4a?

Dec 21, 2016

$2 a + 5$

#### Explanation:

(8a^2+4a)÷4a=(8a^2+20a)/(4a)

We can now divide each of the terms on the numerator by 4a

$\Rightarrow \frac{8 {a}^{2}}{4 a} + \frac{20 a}{4 a}$

simplify each fraction by cancelling.

=(cancel(8)^2cancel(a^2)^a)/(cancel(4)^1cancel(a)^1)+(cancel(20)^5cancel(a)^1)/(cancel(4)^1cancel(a)^1

$= \frac{2 a}{1} + \frac{5}{1} = 2 a + 5 \leftarrow \text{ quotient}$