How do you find the quotient of #(8a^2+20a)div4a#?
1 Answer
Dec 21, 2016
Explanation:
#(8a^2+4a)÷4a=(8a^2+20a)/(4a)# We can now divide each of the terms on the numerator by 4a
#rArr(8a^2)/(4a)+(20a)/(4a)# simplify each fraction by cancelling.
#=(cancel(8)^2cancel(a^2)^a)/(cancel(4)^1cancel(a)^1)+(cancel(20)^5cancel(a)^1)/(cancel(4)^1cancel(a)^1#
#=(2a)/1+5/1=2a+5larr" quotient"#
